9) Proportion Vout/Vin = 470/(120+470)
= 470/590
= 47/59
Vout = 6 * 47/59
= 4.77966101695...
= 4.78 V (3 s.f.)
10) If Vin = 6 V, then
Vout = 15 * 47/59
= 11.9491525424...
= 11.9 V (3 s.f.)
11) Proportion Vout/Vin = 470/(680 + 470)
= 470/1150
= 47/115
Vout = 6 * 47/115
= 2.45217391304...
= 2.45 V (3 s.f.)
12) Vout = 5 V, therefore
5 = Vin * 47/59
Vin = 5 * 59/47
= 6.27659574468...
= 6.28 V (3 s.f.)
When you're coding around in circles and editing line after line of mystifying code in dismay, when you're exhausted, mind numb and flickering in and out of consciousness, from a tenuous session of extreme programming, this is the one place to turn to for that little bit of inspiration, that spark which sets off a genius idea, and the occasional chuckle from a terrible joke or weird phrase.
Tuesday, 7 May 2013
Wednesday, 1 May 2013
Basic resistor knowledge
Here are some pretty pictures to get us going...
| This is basically how a rotary potentiometer (variable resistor) works - twisting the knob changes the amount of metal in the resistor that is used in the circuit, thereby changing the resistance. |
| Here, a variable resistor is connected in a circuit. |
Important points to note:
- Typical pots (potentiometers) are rated to run at a maximum of 0.2W to 0.5W
- The fourth band on a resistor tells us how precise or tolerant the resistor is
- 'Colours of Tolerance': red is +/- 2% tolerance; gold is +/- 5% tolerance; silver 10%; no band 20%
- If there are many resistors connected in series, the total resistance of the circuit is the sum of all the resistors' resistances
- The rate of energy conversion (basically power??) is measured in watts
Important information on voltage dividers:
Working out the total resistance in a parallel circuit:
Questions on Resistance:
- 3.7 A of current flows towards and through R
- The current flowing through R is now 0.2 A in the same direction
- R2 because it has the highest resistance, so the voltage/potential difference will drop the most across it
- V = IR
Making I the subject:
I = V/R
Therefore the current (I) through the circuit is
10/(56 + 120 + 82)
= 10/258
= 5/129
= 0.0388 A (3 s.f.)
= 38.8 mA
V = IR
Therefore,
Voltage across R1 = 0.0388 * 56
= 2.170542635658915...
= 2.17 V (3 s.f.)
Similarly,
Voltage across R2 = 0.0388 * 120
= 4.651162790697675...
= 4.65 V (3 s.f.)
and
Voltage across R3 = 0.0388 * 82
= 3.178294573643411...
= 3.18 V (3 s.f.)
Check: 2.17 + 4.65 + 3.18 = 10 V - YAY!!! I GOT IT RIIIIIGGGHHT!!! - Voltage = 0.03 * 258 = 7.74 V
- Current through R1 = 3/100 = 0.03 A = 30 mA
Current through R2 = 3/47 = 0.06382978723 = 0.0638 A (3 s.f.) = 63.8 mA
Voltages across R1 & R2 are both 3V (obviously!)
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